If a fair coin is tossed 4 times, what is the probability that two heads and two tails will result?
(A) $\dfrac{3}{8}$
(B) $\dfrac{1}{2}$
(C) $\dfrac{5}{8}$
(D) $\dfrac{3}{4}$
(GATE 2004)
Answer: (A) $\dfrac{3}{8}$
Explanation:
Let $X$ be a random variable that denotes the number of heads.
Here, the probability of 'success', $p = \dfrac{1}{2}$, and number of trials, $n = 4$.
Therefore, by the binomial distribution, we get the required probability
$= P(X = 2)$
$= {}^{4}\textrm{C}_{2}\left(\dfrac{1}{2}\right)^{2}\left(\dfrac{1}{2}\right)^{2}$
$= \dfrac{3}{8}$
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